Verified Solution • 2025–26 Session moderate

QJEEM23Ph4cf8: JEE Main 2023 Physics - Class 11 JEEM23Ph4cf8 Solution: The initial speed of a projectile fired from ground is . At the …

The initial speed of a projectile fired from ground is u\mathrm{u} . At the highest point during its motion, the speed of projectile is 32u\frac{\sqrt{3}}{2} u . The time of flight of the projectile is :

Multiple Choice Options

  • A ug\frac{u}{g}
  • B 2ug\frac{2u}{g}
  • C u2g\frac{u}{2g}
  • D 3ug\frac{\sqrt3u}{g}

Step-by-Step Verified Solution

ucos⁡θ=32uu \cos \theta=\frac{\sqrt{3}}{2} u

⇒\Rightarrow cos⁡θ=32\cos \theta=\frac{\sqrt{3}}{2}

⇒\Rightarrow θ=30∘\theta=30^{\circ}

Time of flight =2usin⁡θg=(ug)=\frac{2 u \sin \theta}{g}=\left(\frac{u}{g}\right)

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring