QJEEM23Ph4bcc: JEE Main 2023 Physics - Class 12 JEEM23Ph4bcc Solution: In the following circuit, the magnitude of current I 1 , is…

The indicated diagram shows current flow diagram loops for writing Kirchhoff's law are also indicated, writing the equation

$2{I_3} + {I_1} + {I_3} + {I_2} = 5$

or ${I_1} + {I_2} + 3{I_3} = 5$ ..... (1)

${I_2} - 5 = 2({I_3} - {I_2}) + ({I_1} + {I_3} - {I_2})$

or ${I_1} - 4{I_2} + 3{I_3} = - 5$ ...... (2)

$({I_1} + {I_3}) + ({I_1} + {I_3} - {I_2}) = 2$

or $2{I_1} - {I_2} + 2{I_3} = 2$ ...... (3)

on solving ${I_1} = {3 \over 2}A,{I_2} = 2,{I_3} = {1 \over 2}A$

$= 1.50$