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QJEEM23Ph440c: JEE Main 2023 Physics - Class 11 JEEM23Ph440c Solution: In a screw gauge, there are 100 divisions on the circular scale …

In a screw gauge, there are 100 divisions on the circular scale and the main scale moves by 0.5 mm0.5 \mathrm{~mm} on a complete rotation of the circular scale. The zero of circular scale lies 6 divisions below the line of graduation when two studs are brought in contact with each other. When a wire is placed between the studs, 4 linear scale divisions are clearly visible while 46th 46^{\text {th }} division the circular scale coincide with the reference line. The diameter of the wire is ______________ ×10−2 mm\times 10^{-2} \mathrm{~mm} .

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Least count of screw gauge =0.5100= {{0.5} \over {100}} mm =1200= {{1} \over {200}} mm

Zero error of screw gauge =+6200= +{{6} \over {200}} mm =+3100=0.03= +{{3} \over {100}}=0.03 mm

Reading of screw gauge =4×0.5+46200= 4\times0.5+{{46} \over {200}} mm

=2+23100= 2+{{23} \over {100}} mm =2.23=2.23 mm

So diameter of wire =2.23=2.23 mm − 0.03-~0.03 mm

=2.20=2.20 mm

=220×10−2=220\times10^{-2} mm

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