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QJEEM23Ph40c1: JEE Main 2023 Physics - Class 12 JEEM23Ph40c1 Solution: A metallic cube of side moving along -axis at a uniform…

A metallic cube of side 15 cm15 \mathrm{~cm} moving along yy -axis at a uniform velocity of 2 ms−12 \mathrm{~ms}^{-1} . In a region of uniform magnetic field of magnitude 0.5 T0.5 \mathrm{~T} directed along zz -axis. In equilibrium the potential difference between the faces of higher and lower potential developed because of the motion through the field will be _________ mV.

JEE Main 2023 (Online) 11th April Evening Shift Physics - Electromagnetic Induction Question 34 English

Step-by-Step Verified Solution

amp;qE=eVBamp;E=VB\begin{aligned}& q E=e V B \\\\& E=V B\end{aligned}

ΔVamp;=(E.d)amp;=(VB)×0.15amp;=2×12×0.15 Vamp;=0.15 V=150mV\begin{aligned}\Delta V & =(E . d) \\\\& =(V B) \times 0.15 \\\\& =2 \times \frac{1}{2} \times 0.15 \mathrm{~V} \\\\& =0.15 \mathrm{~V}=150 \mathrm{mV}\end{aligned}

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