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QJEEM23Ph3cf9: JEE Main 2023 Physics - Class 12 JEEM23Ph3cf9 Solution: As per the given figure, if then the value of at this instant…

JEE Main 2023 (Online) 30th January Morning Shift Physics - Electromagnetic Induction Question 46 English

As per the given figure, if dIdt=−1 A/s\frac{\mathrm{dI}}{\mathrm{dt}}=-1 \mathrm{~A} / s then the value of VAB\mathrm{V}_{\mathrm{AB}} at this instant will be ____________ V\mathrm{V} .

Step-by-Step Verified Solution

From the circuit :

VA−iR−Ldidt−12=VB{V_A} - iR - {{Ldi} \over {dt}} - 12 = {V_B}

⇒VA−VB=2×12+6(−1)+12\Rightarrow {V_A} - {V_B} = 2 \times 12 + 6( - 1) + 12 volts

=30= 30 volts

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