QJEEM23Ph3af4: JEE Main 2023 Physics - Class 12 JEEM23Ph3af4 Solution: The magnitude of magnetic induction at mid point due to current …

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The magnitude of magnetic induction at mid point $\mathrm{O}$ due to current arrangement as shown in Fig will be

JEE Main 2023 (Online) 29th January Morning Shift Physics - Magnetic Effect of Current Question 62 English

Accepted Answer

Magnetic field due to wire

A B

and wire

E D

cancel each other. So, magnetic field due to BC and ET will be

\begin{aligned}&amp; B_1=\frac{\mu_0 I}{4 \pi(a / 2)} \cdot\left(\sin \frac{\pi}{2}+\sin 0^{\circ}\right) = \frac{\mu_0 I}{2 \pi a} \\&amp; B_2=\frac{\mu_0 I}{4 \pi(a / 2)} \cdot\left(\sin \frac{\pi}{2}+\sin 0^{\circ}\right) = \frac{\mu_0 I}{2 \pi a}\end{aligned}

So,

B_{\text {net }}=B_1+B_2=\frac{\mu_0 I}{\pi a}

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