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QJEEM23Ph382e: JEE Main 2023 Physics - Class 12 JEEM23Ph382e Solution: A carrier wave of amplitude 15 V is modulated by a sinusoidal…

A carrier wave of amplitude 15 V is modulated by a sinusoidal base band signal of magnitude 3 V. The ratio of maximum amplitude to minimum amplitude in an amplitude modulated wave is

Multiple Choice Options

  • A 1
  • B 5
  • C 2
  • D 32\frac{3}{2}

Step-by-Step Verified Solution

The maximum and minimum amplitude of a modulated wave are given by:

Maximum amplitude = carrier wave amplitude + base band signal magnitude = 15V + 3V = 18V

Minimum amplitude = carrier wave amplitude - base band signal magnitude = 15V - 3V = 12V

Therefore, the ratio of maximum amplitude to minimum amplitude in an amplitude modulated wave is 18/12 = 1.5 or 32\frac{3}{2} .

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