Verified Solution • 2025–26 Session moderate

QJEEM23Ph30b2: JEE Main 2023 Physics - Class 12 JEEM23Ph30b2 Solution: The number of turns of the coil of a moving coil galvanometer…

The number of turns of the coil of a moving coil galvanometer is increased in order to increase current sensitivity by 50%50 \% . The percentage change in voltage sensitivity of the galvanometer will be :

Multiple Choice Options

  • A 0%0 \%
  • B 75%75 \%
  • C 100%100 \%
  • D 50%50 \%

Step-by-Step Verified Solution

Current sensitivity == Voltage sensitivity ×R\times R

Current sensitivity is made 1.51.5 times.

RR also increase 1.51.5 times.

Hence voltage sensitivity =1.5× current sensitivity 1.5×R=\frac{1.5 \times \text { current sensitivity }}{1.5 \times R}

= no change =\text { no change }

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