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QJEEM23Ph28c4: JEE Main 2023 Physics - Class 12 JEEM23Ph28c4 Solution: As shown in the figure, a network of resistors is connected to…

As shown in the figure, a network of resistors is connected to a battery of 24V with an internal resistance of 3 $Ω$ . The currents through the resistors R $_{4}$ and R $_{5}$ are I $_{4}$ and I $_{5}$ respectively. The values of I $_{4}$ and I $_{5}$ are :

JEE Main 2023 (Online) 24th January Morning Shift Physics - Current Electricity Question 84 English

Multiple Choice Options

A I4=85A and I5=25A
B I4=65A and I5=245A
C I4=25A and I5=85A
D I4=245A and I5=65A

Step-by-Step Verified Solution

Equivalent resistance of circuit

\begin{aligned} R_{eq} & = 3 + 1 + 2 + 4 + 2 \\ = 12 Ω \end{aligned}

Current through battery

\mathrm{i}=\frac{24}{12}=2 \mathrm{~A}

\begin{aligned} I_{4} = \frac{R_{5}}{R_{4} + R_{5}} \times 2 = \frac{5}{20 + 5} \times 2 = \frac{2}{5} A \\ I_{5} = 2 - \frac{2}{5} = \frac{8}{5} A \end{aligned}

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