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QJEEM23Ph26e2: JEE Main 2023 Physics - Class 12 JEEM23Ph26e2 Solution: For designing a voltmeter of range and an ammeter of range…

For designing a voltmeter of range 50 V50 \mathrm{~V} and an ammeter of range 10 mA10 \mathrm{~mA} using a galvanometer which has a coil of resistance 54Ω54 \Omega showing a full scale deflection for 1 mA1 \mathrm{~mA} as in figure.

JEE Main 2023 (Online) 15th April Morning Shift Physics - Current Electricity Question 82 English

(A) for voltmeter R≈50kΩR \approx 50 \mathrm{k} \Omega

(B) for ammeter r≈0.2Ω\mathrm{r} \approx 0.2 \Omega

(C) for ammeter r=6Ω\mathrm{r}=6 \Omega

(D) for voltmeter R≈5kΩR \approx 5 \mathrm{k} \Omega

(E) for voltmeter R≈500ΩR \approx 500 \Omega

Choose the correct answer from the options given below:

Multiple Choice Options

  • A (A)(\mathrm{A}) and (C)(\mathrm{C})
  • B (A) and (B)
  • C (C) and (E)
  • D (C) and (D)

Step-by-Step Verified Solution

For voltmeter

R=VIg−G=5010−3−54≈50kΩ (A)

For ammeter

S=IgGI−Ig=10−3×54(10−1)×10−3=6Ω (C)

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