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QJEEM23Ph2322: JEE Main 2023 Physics - Class 11 JEEM23Ph2322 Solution: For a simple harmonic motion in a mass spring system shown, the …

For a simple harmonic motion in a mass spring system shown, the surface is frictionless. When the mass of the block is 1 kg1 \mathrm{~kg} , the angular frequency is ω1\omega_{1} . When the mass block is 2 kg2 \mathrm{~kg} the angular frequency is ω2\omega_{2} . The ratio ω2/ω1\omega_{2} / \omega_{1} is

JEE Main 2023 (Online) 30th January Evening Shift Physics - Simple Harmonic Motion Question 41 English

Multiple Choice Options

  • A 1/21 / \sqrt{2}
  • B 1/21 / 2
  • C 2
  • D 2\sqrt{2}

Step-by-Step Verified Solution

ω=Km⇒ω∝1m\omega = \sqrt {{K \over m}} \Rightarrow \omega \propto {1 \over {\sqrt m }}

ω2ω1=m1m2=12{{{\omega _2}} \over {{\omega _1}}} = \sqrt {{{{m_1}} \over {{m_2}}}} = \sqrt {{1 \over 2}}

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