QJEEM23Ph17cf: JEE Main 2023 Physics - Class 12 JEEM23Ph17cf Solution: An alternating voltage source ) is connected across a pure…

Question

Verified Solution • 2025–26 Session moderate

An alternating voltage source

\mathrm{V}=260 \sin (628 \mathrm{t}

) is connected across a pure inductor of

5 \mathrm{mH}

Inductive reactance in the circuit is :

Accepted Answer

\omega

= 628 rad/s

X_{L}=L \omega

\begin{aligned} = 5 mH \times 628 \\ = 3.14 Ω \end{aligned}

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