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QJEEM23Ph16cd: JEE Main 2023 Physics - Class 11 JEEM23Ph16cd Solution: An object moves at a constant speed along a circular path in a…

An object moves at a constant speed along a circular path in a horizontal plane with center at the origin. When the object is at x=+2 m, its velocity is −4j^ m/s. The object's velocity (v) and acceleration (a) at x=−2 m will be

Multiple Choice Options

  • A v=4i^ m/s,a=8j^ m/s2
  • B v=4j^ m/s,a=8i^ m/s2
  • C v=−4i^ m/s,a=−8j^ m/s2
  • D v=−4j^ m/s,a=8i^ m/s2

Step-by-Step Verified Solution

JEE Main 2023 (Online) 29th January Evening Shift Physics - Circular Motion Question 28 English Explanation

v→=4j^ (m/s)

a=v2R=162=8 m/s2

a→=8(m/s2)(i^)

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