Verified Solution • 2025–26 Session moderate

QJEEM23Ph053f: JEE Main 2023 Physics - Class 12 JEEM23Ph053f Solution: Given below are two statements : Statement I : If the…

Given below are two statements :

Statement I : If the Brewster's angle for the light propagating from air to glass is θB\mathrm{\theta_B} , then the Brewster's angle for the light propagating from glass to air is π2−θB\frac{\pi}{2}-\theta_B

Statement II : The Brewster's angle for the light propagating from glass to air is tan⁡−1(μg){\tan ^{ - 1}}({\mu _\mathrm{g}}) where μg\mathrm{\mu_g} is the refractive index of glass.

In the light of the above statements, choose the correct answer from the options given below :

Multiple Choice Options

  • A Both Statement I and Statement II are false
  • B Both Statement I and Statement II are true
  • C Statement I is false but Statement II is true
  • D Statement I is true but Statement II is false

Step-by-Step Verified Solution

Case I :

JEE Main 2023 (Online) 24th January Morning Shift Physics - Wave Optics Question 40 English Explanation 1

Transmitted is ⊥\perp to reflected.

i+r=90∘i+r=90^{\circ}

Snell's law

μasin⁡i=μgsin⁡r\mu_{a} \sin i=\mu_{g} \sin r

tan⁡i=μgμa\tan i=\frac{\mu_{g}}{\mu_{a}}

i=tan⁡−1(μgμa)=θBi=\tan ^{-1}\left(\frac{\mu_{g}}{\mu_{a}}\right)=\theta_{B}

Case II :

JEE Main 2023 (Online) 24th January Morning Shift Physics - Wave Optics Question 40 English Explanation 2

i+r=90∘i+r=90^{\circ} as transmitted is ⊥\perp to reflected.

tan⁡i=μaμg⇒i=tan⁡−1μaμg=π2−θB\tan i=\frac{\mu_{a}}{\mu_{g}} \Rightarrow i=\tan ^{-1} \frac{\mu_{a}}{\mu_{g}}=\frac{\pi}{2}-\theta_{B}

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring