Verified Solution • 2025–26 Session moderate

QJEEM23Ph0077: JEE Main 2023 Physics - Class 12 JEEM23Ph0077 Solution: An ice cube has a bubble inside. When viewed from one side the…

An ice cube has a bubble inside. When viewed from one side the apparent distance of the bubble is 12 cm12 \mathrm{~cm} . When viewed from the opposite side, the apparent distance of the bubble is observed as 4 cm4 \mathrm{~cm} . If the side of the ice cube is 24 cm24 \mathrm{~cm} , the refractive index of the ice cube is

Multiple Choice Options

  • A 32\frac{3}{2}
  • B 43\frac{4}{3}
  • C 23\frac{2}{3}
  • D 65\frac{6}{5}

Step-by-Step Verified Solution

Let's denote the true distance of the bubble from one side of the ice cube as xx and the refractive index of the ice cube as nn . We will use the formula for apparent depth, which states that the ratio of the true depth to the apparent depth is equal to the refractive index:

n=True depthApparent depthn = \frac{\text{True depth}}{\text{Apparent depth}}

When viewing the bubble from one side, the true depth is xx and the apparent depth is 12 cm12 \mathrm{~cm} . Using the formula:

n=x12n = \frac{x}{12}

When viewing the bubble from the opposite side, the true depth is 24−x24 - x (since the side of the ice cube is 24 cm24 \mathrm{~cm} ) and the apparent depth is 4 cm4 \mathrm{~cm} . Using the formula:

n=24−x4n = \frac{24 - x}{4}

Now we have a system of two equations with two variables:

1) n=x12n = \frac{x}{12}

2) n=24−x4n = \frac{24 - x}{4}

We can solve this system by setting the two expressions for nn equal to each other:

x12=24−x4\frac{x}{12} = \frac{24 - x}{4}

To solve for xx , first multiply both sides by 1212 :

x=3(24−x)x = 3(24 - x)

x=72−3xx = 72 - 3x

Add 3x3x to both sides:

4x=724x = 72

Divide by 44 :

x=18x = 18

Now that we have the value of xx , we can find the refractive index nn using either equation 1 or 2. Using equation 1:

n=1812=32n = \frac{18}{12} = \frac{3}{2}

Therefore, the refractive index of the ice cube is 32\frac{3}{2} .

Related Learning Resources & Exam Preparation