Verified Solution • 2025–26 Session moderate

QJEEM23Maf318: JEE Main 2023 Mathematics - Class 11 JEEM23Maf318 Solution: The statement is

The statement (p∧(∼q))⇒(p⇒(∼q))\left( {p \wedge \left( { \sim q} \right)} \right) \Rightarrow \left( {p \Rightarrow \left( { \sim q} \right)} \right) is

Multiple Choice Options

  • A a tautology
  • B equivalent to (∼p)∨(∼q)\left( { \sim p} \right) \vee \left( { \sim q} \right)
  • C a contradiction
  • D p∨qp \vee q

Step-by-Step Verified Solution

Making truth table (Let (p∧∼q)⇒(p⇒∼q)=E(p \wedge \sim q) \Rightarrow(p \Rightarrow \sim q)=E )

pp qq ∼p\sim p ∼q\sim q p∧∼qp \wedge \sim q p⇒∼qp \Rightarrow \sim q EE
T\mathrm{T} T\mathrm{T} F\mathrm{F} F\mathrm{F} F\mathrm{F} F\mathrm{F} T\mathrm{T}
T\mathrm{T} F\mathrm{F} F\mathrm{F} T\mathrm{T} T\mathrm{T} T\mathrm{T} T\mathrm{T}
F\mathrm{F} T\mathrm{T} T\mathrm{T} F\mathrm{F} F\mathrm{F} T\mathrm{T} T\mathrm{T}
F\mathrm{F} F\mathrm{F} T\mathrm{T} T\mathrm{T} F\mathrm{F} T\mathrm{T} T\mathrm{T}

∴E\therefore E is a tautology

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