JEE Main 2023 Mathematics - Class 11 JEEM23Mae294 Solution: The constant term in the expansion of is ___________.

Constant term in the expansion of

\begin{aligned}&amp; \left(2 x+\frac{1}{x^{7}}+3 x^{2}\right)^{5} \\\\&amp; \frac{1}{x^{35}}\left(2 x^{8}+1+3 x^{9}\right)^{5} \\\\&amp; \frac{1}{x^{35}}\left(1+x^{8}(3 x+2)\right)^{5}\end{aligned}

Term independent of

x=

coefficient of

x^{35}

\begin{aligned}&amp; ^{5} C_{4}\left(x^{8}(3 x+2)\right)^{4} \\\\= &amp; { }^{5} C_{4} \text { coefficient of } x^{3} \text { in }(2+3 x)^{4} \\\\= &amp; { }^{5} C_{4} \times{ }^{4} C_{3}(2)^{1}(3)^{3} \\\\= &amp; 5 \times 4 \times 2 \times 27 \\\\= &amp; 1080\end{aligned}

QJEEM23Mae294: JEE Main 2023 Mathematics - Class 11 JEEM23Mae294 Solution: The constant term in the expansion of is ___________.