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QJEEM23Mad95c: JEE Main 2023 Mathematics - Class 11 JEEM23Mad95c Solution: The number of integral terms in the expansion of is equal to…

The number of integral terms in the expansion of (312+514)680\left(3^{\frac{1}{2}}+5^{\frac{1}{4}}\right)^{680} is equal to ___________.

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amp; General term of the expansion (312+514)680amp;=680Cr(31/2)680−r(51/4)r=680Cr×3680−r2×5r4\begin{aligned}& \text { General term of the expansion }\left(3^{\frac{1}{2}}+5^{\frac{1}{4}}\right)^{680} \\\\& \qquad={ }^{680} C_r\left(3^{1 / 2}\right)^{680-r}\left(5^{1 / 4}\right)^r={ }^{680} C_r \times 3^{\frac{680-r}{2}} \times 5^{\frac{r}{4}}\end{aligned}

The term will be integral if rr is a multiple of 4 .

∴r=0,4,8,12,…,680( which is an AP)680=0+(n−1)4n=6804+1=171\begin{gathered}\therefore r=0,4,8,12, \ldots, 680(\text { which is an } \mathrm{AP}) \\\\680=0+(n-1) 4 \\\\n=\frac{680}{4}+1=171\end{gathered}

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