The given expression is
(ax−bx21)13 So,
Tr+1amp;=13Cr(ax)13−r(−bx21)ramp;=13Cr(a)13−rx13−r−2r(−1/b)ramp;=13Cr(a)13−r(−b1)rx13−3r For coefficient of
x7 in
(ax−bx21)13 amp;13−3r=7amp;⇒3r=6⇒r=2amp;∴ Coefficient of x7=13C2⋅(a)11⋅b21 Again, the another expression is
(ax+bx21)13 So,
Tn+1=13Cr(ax)13−r(bx21)r=13Cr(a)13−r(b1)rx13−3r For coefficient
x−5 in
(ax+bx21)13 amp;13−3r=−5amp;⇒r=6 So, coefficient of
x−5=13C6(a)7b61 Now, according to the question,
13C2(a)11b21=13C6(a)7b61 amp;⇒a4b4=13C213C6amp;∴a4b4=22