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QJEEM23Mab8d8: JEE Main 2023 Mathematics - Class 11 JEEM23Mab8d8 Solution: The range of f ( x ) = 4 sin − 1 ⁡ ( x 2 x 2 + 1 ) is

The range of f(x)=4sin−1⁡(x2x2+1) is

Multiple Choice Options

  • A [0,2π]
  • B [0,2π)
  • C [0,π)
  • D [0,π]

Step-by-Step Verified Solution

x21+x2=1−11+x2<1∴0≤x21+x2<1⇒0≤sin−1⁡(x21+x2)<π2⇒0≤4sin−1⁡(x21+x2)<2π

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