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QJEEM23Maafb2: JEE Main 2023 Mathematics - Class 11 JEEM23Maafb2 Solution: Let . Then the number of possible functions such that for every …

Let A={1,2,3,5,8,9}A=\{1,2,3,5,8,9\} . Then the number of possible functions f:A→Af: A \rightarrow A such that f(m⋅n)=f(m)⋅f(n)f(m \cdot n)=f(m) \cdot f(n) for every m,n∈Am, n \in A with m⋅n∈Am \cdot n \in A is equal to ___________.

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f(1.n)=f(1).f(n)⇒f(1)=1.

f(3.3)=(f(3))2

Hence, the possibilities for (t(3),(9)) are (1,1) and (3,9).

Other three i.e. f(2),f(5),f(8)

Can be chosen in 63 ways.

Hence, total number of functions

63×2=432

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