Verified Solution • 2025–26 Session moderate

QJEEM23Ma9cca: JEE Main 2023 Mathematics - Class 11 JEEM23Ma9cca Solution: Among the statements (S1) : ( p ⇒ q ) ∨ ( ( ∼ p ) ∧ q ) is a…

Among the statements

(S1) : (p⇒q)∨((∼p)∧q) is a tautology

(S2) : (q⇒p)⇒((∼p)∧q) is a contradiction

Multiple Choice Options

  • A neither (S1) and (S2) is True
  • B only (S2) is True
  • C both (S1) and (S2) are True
  • D only (S1) is True

Step-by-Step Verified Solution

(S1) : (p⇒q)∨((∼p)∧q)

PQ∼p∼p∧qp⇒q(p⇒q)∨(∼p∧q)TTFFTTTFFFFFFTTTTTFFTFTT

Here, for every value of components compound statement (last column) are not true. Hence, S1S_1 is not a tautology.

S2:(q⇒p)⇒((∼p)∧q)S_2:(q \Rightarrow p) \Rightarrow((\sim p) \wedge q)

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