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QJEEM23Ma8649: JEE Main 2023 Mathematics - Class 11 JEEM23Ma8649 Solution: The coefficient of , in the expansion of , is

The coefficient of x−6x^{-6} , in the

expansion of (4x5+52x2)9\left(\frac{4 x}{5}+\frac{5}{2 x^{2}}\right)^{9} , is

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Coeff of x−6x^{-6} in (4x5+52x2)9\left(\frac{4 x}{5}+\frac{5}{2 x^{2}}\right)^{9}

Tr+1=9Cr(4x5)9−r(52x2)r9−3r=−6r=5

Coeff of x−6=9C5(45)4(52)5x^{-6}={ }^{9} C_{5}\left(\frac{4}{5}\right)^{4}\left(\frac{5}{2}\right)^{5} =5040

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