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QJEEM23Ma85c2: JEE Main 2023 Mathematics - Class 11 JEEM23Ma85c2 Solution: Five digit numbers are formed using the digits 1, 2, 3, 5, 7…

Five digit numbers are formed using the digits 1, 2, 3, 5, 7 with repetitions and are written in descending order with serial numbers. For example, the number 77777 has serial number 1. Then the serial number of 35337 is ____________.

Step-by-Step Verified Solution

Descending order means from highest to lowest.

∴\therefore Descending order of digits 1, 2, 3, 5, 7 is = 7, 5, 3, 2, 1.

(1) Number starts with 7 :

JEE Main 2023 (Online) 29th January Morning Shift Mathematics - Permutations and Combinations Question 65 English Explanation 1

∴\therefore Total possible numbers start's with 7 are = 5C1 ×\times 5C1 ×\times 5C1 ×\times 5C1 = 54

(2) Number of starts with 5 :

JEE Main 2023 (Online) 29th January Morning Shift Mathematics - Permutations and Combinations Question 65 English Explanation 2

∴\therefore Total possible numbers start's with 5 are = 5C1 ×\times 5C1 ×\times 5C1 ×\times 5C1 = 54

(3) Number starts with 37 :

JEE Main 2023 (Online) 29th January Morning Shift Mathematics - Permutations and Combinations Question 65 English Explanation 3

∴\therefore Total possible numbers starts with 3 and 7 are = 5C1 ×\times 5C1 ×\times 5C1 = 53

(4) Number starts with 357 :

JEE Main 2023 (Online) 29th January Morning Shift Mathematics - Permutations and Combinations Question 65 English Explanation 4

∴\therefore Total possible numbers starts with 357 are = 5C1 ×\times 5C1 = 52

(5) Number starts with 355 :

JEE Main 2023 (Online) 29th January Morning Shift Mathematics - Permutations and Combinations Question 65 English Explanation 5

∴\therefore Total possible numbers starts with 355 are = 5C1 ×\times 5C1 = 52

(6) Number starts with 3537 :

JEE Main 2023 (Online) 29th January Morning Shift Mathematics - Permutations and Combinations Question 65 English Explanation 6

∴\therefore Total possible numbers starts with 3537 are = 5C1 = 5

(7) Number starts with 3535 :

JEE Main 2023 (Online) 29th January Morning Shift Mathematics - Permutations and Combinations Question 65 English Explanation 7

∴\therefore Total possible numbers starts with 3535 are = 5C1 = 5

(8) Next number is 35337 which is the required number.

∴\therefore Position of the number 35337 is = 54 + 54 + 53 + 52 + 52 + 5 + 5 + 1 = 1436

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