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QJEEM23Ma7cff: JEE Main 2023 Mathematics - Class 12 JEEM23Ma7cff Solution: Let be the maximum integral value of in for which the roots of…

Let qq be the maximum integral value of pp in [0,10][0,10] for which the roots of the equation x2−px+54p=0x^2-p x+\frac{5}{4} p=0 are rational. Then the area of the region {(x,y):0≤y≤(x−q)2,0≤x≤q}\left\{(x, y): 0 \leq y \leq(x-q)^2, 0 \leq x \leq q\right\} is :

Multiple Choice Options

  • A 1253\frac{125}{3}
  • B 243
  • C 164
  • D 25

Step-by-Step Verified Solution

Given equation : 4x2−4px+5p=04{x^2} - 4px + 5p = 0

JEE Main 2023 (Online) 30th January Evening Shift Mathematics - Area Under The Curves Question 54 English Explanation

for rational roots, D must be perfect square

D=16p2−4×4×5p=16p(p−5)D = 16{p^2} - 4 \times 4 \times 5p = 16p(p - 5)

So, max. Integral value of p=9p = 9 for making D is perfect square

∴\therefore q=9q = 9

Area of shared region

=∫09(x−9)2dx= \int\limits_0^9 {{{(x - 9)}^2}dx}

=(x−9)33∣09=933=243= \left. {{{{{(x - 9)}^3}} \over 3}} \right|_0^9 = {{{9^3}} \over 3} = 243 sq. units

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