Verified Solution • 2025–26 Session moderate

QJEEM23Ma7624: JEE Main 2023 Mathematics - Class 11 JEEM23Ma7624 Solution: Let A = { 1 , 2 , 3 , 4 , 5 , 6 , 7 } . Then the relation R = { …

Let A={1,2,3,4,5,6,7}. Then the relation R={(x,y)∈A×A:x+y=7} is :

Multiple Choice Options

  • A reflexive but neither symmetric nor transitive
  • B transitive but neither symmetric nor reflexive
  • C symmetric but neither reflexive nor transitive
  • D an equivalence relation

Step-by-Step Verified Solution

Here, A={1,2,3,4,5,6,7}A=\{1,2,3,4,5,6,7\}

Since, x+y=7⇒y=7−xx+y=7 \Rightarrow y=7-x

So, R={(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)}\mathrm{R}=\{(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)\}

∵(a,b)∈R⇒(b,a)∈R\because(a, b) \in \mathrm{R} \Rightarrow(b, a) \in \mathrm{R}

∴R\therefore \mathrm{R} is symmetric only.

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