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QJEEM23Ma5953: JEE Main 2023 Mathematics - Class 11 JEEM23Ma5953 Solution: Let denote the greatest integer . Then is equal to __________

Let [α][\alpha] denote the greatest integer ≤α\leq \alpha . Then [1]+[2]+[3]+…+[120][\sqrt{1}]+[\sqrt{2}]+[\sqrt{3}]+\ldots+[\sqrt{120}] is equal to __________

Step-by-Step Verified Solution

amp;[1]+[2]+[3]+….+[120]amp;E=1+1+1+2+2+2+2+2+3+3+3+3+3amp;+3+3+4+4+…amp;E=3×1+5×2+7×3+….+19×9+10×21amp;=∑r=110(2r+1)r=2[10×11×216]+10×112amp;=770+55amp;=825amp;\begin{aligned}& {[\sqrt{1}]+[\sqrt{2}]+[\sqrt{3}]+\ldots .+[120]} \\\\& E=1+1+1+2+2+2+2+2+3+3+3+3+3 \\\\& +3+3+4+4+\ldots \\\\& E=3 \times 1+5 \times 2+7 \times 3+\ldots .+19 \times 9+10 \times 21 \\\\& =\sum_{r=1}^{10}(2 r+1) r=2\left[\frac{10 \times 11 \times 21}{6}\right]+\frac{10 \times 11}{2} \\\\& =770+55 \\\\& =825 \\\\&\end{aligned}

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