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QJEEM23Ma529b: JEE Main 2023 Mathematics - Class 12 JEEM23Ma529b Solution: If the area of the region bounded by the curves is A, then 8 A…

If the area of the region bounded by the curves y2−2y=−x,x+y=0y^2-2y=-x,x+y=0 is A, then 8 A is equal to __________

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Area enclosed by

amp;y2−2y=−xamp;x+y=0\begin{aligned}& y^{2}-2 y=-x \\\\& x+y=0\end{aligned}

JEE Main 2023 (Online) 24th January Evening Shift Mathematics - Area Under The Curves Question 46 English Explanation
Area =∫03(2y−y2)−(−y)dy=\int_{0}^{3}\left(2 y-y^{2}\right)-(-y) d y

=∫03(3y−y2)dy=\int_{0}^{3}\left(3 y-y^{2}\right) d y

amp;=3y22−y33]03amp;=272−9amp;=27−182=92=A\begin{aligned}& \left.=\frac{3 y^{2}}{2}-\frac{y^{3}}{3}\right]_{0}^{3} \\\\& =\frac{27}{2}-9 \\\\& =\frac{27-18}{2}=\frac{9}{2}=A\end{aligned}

8A=92×8=368 A=\frac{9}{2} \times 8=36 sq. units

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