Verified Solution • 2025–26 Session moderate

QJEEM23Ma4a8a: JEE Main 2023 Mathematics - Class 11 JEEM23Ma4a8a Solution: Let R be a relation on R , given by R = { ( a , b ) : 3 a − 3 b …

Let R be a relation on R, given by R={(a,b):3a−3b+7 is an irrational number }. Then R is

Multiple Choice Options

  • A an equivalence relation
  • B reflexive and symmetric but not transitive
  • C reflexive and transitive but not symmetric
  • D reflexive but neither symmetric nor transitive

Step-by-Step Verified Solution

For reflexive :

3a−3a+73 a-3 a+\sqrt{7} is an irrational number ∀a∈RR\forall a \in R R is reflexive

For symmetric :

Let 3a−3b+73 a-3 b+\sqrt{7} is an irrational number

⇒3b−3a+7\Rightarrow 3 b-3 a+\sqrt{7} is an irrational number

For example, Let 3a−3b=73 a-3 b=\sqrt{7}

7+7\sqrt{7}+\sqrt{7} is irrational but −7+7-\sqrt{7}+\sqrt{7} is not.

∴R\therefore R is not symmetric

For transitive :

Let 3a−3b+73 a-3 b+\sqrt{7} is irrational and 3b−3c+73 b-3 c+\sqrt{7} is irrational.

⇒3a−3c+7\Rightarrow 3 a-3 c+\sqrt{7} is irrational.

For example, take a=0,b=−7,c=73a=0, b=-\sqrt{7}, c=\frac{\sqrt{7}}{3}

RR is not transitive.

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