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QJEEM23Ma3ef5: JEE Main 2023 Mathematics - Class 12 JEEM23Ma3ef5 Solution: Let be the area bounded by the curve , the -axis and the…

Let AA be the area bounded by the curve y=x∣x−3∣y=x|x-3| , the xx -axis and the ordinates x=−1x=-1 and x=2x=2 . Then 12A12 A is equal to ____________.

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JEE Main 2023 (Online) 1st February Morning Shift Mathematics - Area Under The Curves Question 56 English Explanation

=∫−12∣3x−x2∣=\int\limits_{-1}^{2}\left|3 x-x^{2}\right|

A=∫−10x2−3xdx+∫023x−x2dxA=\int\limits_{-1}^{0} x^{2}-3 x d x+\int\limits_{0}^{2} 3 x-x^{2} d x

=x33−3x22]−10+3x22−x33]02\left.\left.=\frac{x^{3}}{3}-\frac{3 x^{2}}{2}\right]_{-1}^{0}+\frac{3 x^{2}}{2}-\frac{x^{3}}{3}\right]_{0}^{2}

=0−(−13−32)+(6−83)−0=0-\left(\frac{-1}{3}-\frac{3}{2}\right)+\left(6-\frac{8}{3}\right)-0

=316=\frac{31}{6}

∴12A=62\therefore 12 A=62

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