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QJEEM23Ma3cd2: JEE Main 2023 Mathematics - Class 11 JEEM23Ma3cd2 Solution: The coefficient of in is ___________.

The coefficient of x7x^7 in (1−x+2x3)10{(1 - x + 2{x^3})^{10}} is ___________.

Step-by-Step Verified Solution

Given expression is (1−x+2x3)10\left(1-x+2 x^3\right)^{10}

So, general term is 10!r1!r2!r3!(1)r1(−1)r2⋅(2)r3⋅(x)r2+r3\frac{10 !}{r_{1} ! r_{2} ! r_{3} !}(1)^{r_1}(-1)^{r_2} \cdot(2)^{r_3} \cdot(x)^{r_2+r_3}

Where, r1+r2+r3=10r_1+r_2+r_3=10 and r2+3r3=7r_2+3 r_3=7

Now, for possibility,

r1amp;r2amp;r33amp;7amp;07amp;1amp;25amp;4amp;1\begin{array}{ccc}r_1 & r_2 & r_3 \\ 3 & 7 & 0 \\ 7 & 1 & 2 \\ 5 & 4 & 1\end{array}

Thus, required co-efficient

amp;=10!3!7!(−1)7+10!5!4!(−1)4(2)+10!7!2!(−1)1(2)2amp;=−120+2520−1440amp;=2520−1560=960\begin{aligned}& =\frac{10 !}{3 ! 7 !}(-1)^7+\frac{10 !}{5 ! 4 !}(-1)^4(2)+\frac{10 !}{7 ! 2 !}(-1)^1(2)^2 \\\\& =-120+2520-1440 \\\\& =2520-1560=960\end{aligned}

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