QJEEM23Ma116c: JEE Main 2023 Mathematics - Class 12 JEEM23Ma116c Solution: The area enclosed by the curves y 2 + 4 x = 4 and y − 2 x = 2…

Question

Verified Solution • 2025–26 Session moderate

The area enclosed by the curves $y^{2} + 4 x = 4$ and $y - 2 x = 2$ is :

Accepted Answer

Required area

=\int_{-4}^{2}\left(\frac{4-y^{2}}{4}-\frac{y-2}{2}\right) d y

=\int_{-4}^{2} \frac{8-2 y-y^{2}}{4} d y

=\frac{1}{4}\left\{8 y-y^{2}-\frac{y^{3}}{3}\right\}_{-4}^{2}

=9

square units

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