Verified Solution • 2025–26 Session moderate

QJEEM23Ma02b8: JEE Main 2023 Mathematics - Class 11 JEEM23Ma02b8 Solution: Among the statements : ( S 1 )   ( ( p ∨ q ) ⇒ r ) ⇔ ( p ⇒ …

Among the statements :

(S1) ((p∨q)⇒r)⇔(p⇒r)

(S2) ((p∨q)⇒r)⇔((p⇒r)∨(q⇒r))

Multiple Choice Options

  • A only (S1) is a tautology
  • B neither (S1) nor (S2) is a tautology
  • C both (S1) and (S2) are tautologies
  • D only (S2) is a tautology

Step-by-Step Verified Solution

S1:((p∨q)⇒r)⇔(p⇒r)

S2:((p∨q)⇒r)⇔((p⇒r)∨(q⇒r))

In S1: If p=F,q=T,r=F then S1 is false

In S2: If p=T,q=F,r=F then S2 is false

∴ Neither S1 nor S2 is a tautology

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