Verified Solution • 2025–26 Session moderate

QJEEM23Chfb84: JEE Main 2023 Chemistry - Class 11 JEEM23Chfb84 Solution: The volume of HCl, containing 73 g L , required to completely…

The volume of HCl, containing 73 g L −1^{-1} , required to completely neutralise NaOH obtained by reacting 0.69 g of metallic sodium with water, is __________ mL. (Nearest Integer)

(Given : molar masses of Na, Cl, O, H, are 23, 35.5, 16 and 1 g mol −1^{-1} respectively.)

Step-by-Step Verified Solution

Na+H2O0.69 g→NaOH+12H20.03 moles\mathrm{\mathop {Na + {H_2}O}\limits_{0.69\,g} \to \mathop {NaOH + {1 \over 2}{H_2}}\limits_{0.03\,moles}}

= 0.03 moles

∴0.03=2×V\therefore 0.03=2\times\mathrm{V}

V=0.032L\mathrm{V=\frac{0.03}{2}L}

= 15 mL

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