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QJEEM23Chfa94: JEE Main 2023 Chemistry - Class 12 JEEM23Chfa94 Solution: In a reaction, reagents 'X' and 'Y' respectively are :

In a reaction,

JEE Main 2023 (Online) 1st February Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 75 English

reagents 'X' and 'Y' respectively are :

Multiple Choice Options

  • A CH3OH/H+,Δ\mathrm{CH}_{3} \mathrm{OH} / \mathrm{H}^{+}, \Delta and (CH3CO)2O/H+\left(\mathrm{CH}_{3} \mathrm{CO}\right)_{2} \mathrm{O} / \mathrm{H}^{+}
  • B (CH3CO)2O/H+\left(\mathrm{CH}_{3} \mathrm{CO}\right)_{2} \mathrm{O} / \mathrm{H}^{+} and CH3OH/H+,Δ\mathrm{CH}_{3} \mathrm{OH} / \mathrm{H}^{+}, \Delta
  • C CH3OH/H+,Δ\mathrm{CH}_{3} \mathrm{OH} / \mathrm{H}^{+}, \Delta and CH3OH/H+,Δ\mathrm{CH}_{3} \mathrm{OH} / \mathrm{H}^{+}, \Delta
  • D (CH3CO)2O/H+\left(\mathrm{CH}_{3} \mathrm{CO}\right)_{2} \mathrm{O} / \mathrm{H}^{+} and (CH3CO)2O/H+\left(\mathrm{CH}_{3} \mathrm{CO}\right)_{2} \mathrm{O} / \mathrm{H}^{+}

Step-by-Step Verified Solution

JEE Main 2023 (Online) 1st February Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 75 English Explanation

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