QJEEM23Chfa2a: JEE Main 2023 Chemistry - Class 12 JEEM23Chfa2a Solution: In figure, a straight line is given for Freundrich Adsorption ( …

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In figure, a straight line is given for Freundrich Adsorption ( $y=3x+2.505$ ). The value of $\frac{1}{n}$ and $\log \mathrm{K}$ are respectively.

JEE Main 2023 (Online) 1st February Evening Shift Chemistry - Surface Chemistry Question 26 English

Accepted Answer

\begin{aligned} &amp; \frac{x}{m}=k p^{1 / n} \\\\ &amp; \log \frac{x}{m}=\log k+\frac{1}{n} \log P\end{aligned}

On comparing with

y=3x+2.505

, we get

\frac{1}{n}=3 \text { and } \log k=2.505

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