QJEEM23Chf4ee: JEE Main 2023 Chemistry - Class 12 JEEM23Chf4ee Solution: A(g) 2B(g) + C(g) is a first order reaction. The initial…

At 10 minutes, the pressure increased by 2x:

$800 + 2x = 1600$

$2x = 800$

$x = 400$

The rate constant (k) can be found as:

$k = \frac{2.303}{10} \log \frac{800}{400} = \frac{2.303 \times \log 2}{10}$

For 30 minutes, we can set up the equation:

$k = \frac{2.303}{30} \log \frac{800}{800 - y}$

$\frac{2.303 \times \log 2}{10} = \frac{2.303}{30} \log \left(\frac{800}{800 - y}\right)$

Solving for y:

$\left(\frac{800}{800 - y}\right) = 8$

$800 - y = 100$

$y = 700$

Now we can find the total pressure after 30 minutes:

Total pressure = (800 - y) + 2y + y

Total pressure = 100 + 1400 + 700

Total pressure = 2200 mm Hg

So, the total pressure of the system after 30 minutes is 2200 mm Hg.