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QJEEM23Chef07: JEE Main 2023 Chemistry - Class 11 JEEM23Chef07 Solution: 1 mole of ideal gas is allowed to expand reversibly and…

1 mole of ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27∘C27^{\circ} \mathrm{C} . The work done is 3 kJ mol−13 \mathrm{~kJ} \mathrm{~mol}^{-1} . The final temperature of the gas is ________ K\mathrm{K} (Nearest integer).

Given CV=20 J mol−1 K−1\mathrm{C_V}=20 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}

Step-by-Step Verified Solution

T1=300 K

w=3 kJ/mole

w=nCvΔT

3000=1×20×(300−T2)

300−T2=150

T2=150 K

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