Verified Solution • 2025–26 Session moderate

QJEEM23Chedea: JEE Main 2023 Chemistry - Class 11 JEEM23Chedea Solution: 600   mL of 0.01   M   HCl is mixed with 400…

600 mL of 0.01 M HCl is mixed with 400 mL of 0.01 M H2SO4. The pH of the mixture is ___________ ×10−2. (Nearest integer)

[Given log⁡2=0.30

log⁡3=0.48

log⁡5=0.69

log⁡7=0.84

log⁡11=1.04]

Step-by-Step Verified Solution

[H+]=6+81000=14×10−3

pH=3−log⁡14

=3−.3−.84

=1.86=186×10−2

Related Learning Resources & Exam Preparation