Verified Solution • 2025–26 Session moderate

QJEEM23Cheb7b: JEE Main 2023 Chemistry - Class 11 JEEM23Cheb7b Solution: Reaction of BeO with ammonia and hydrogen fluoride gives A…

Reaction of BeO with ammonia and hydrogen fluoride gives A which on thermal decomposition gives BeF2\mathrm{BeF_2} and NH4F\mathrm{NH_4F} . What is 'A'?

Multiple Choice Options

  • A (NH4)Be2F5\mathrm{(NH_4)Be_2F_5}
  • B (NH4)2BeF4\mathrm{(NH_4)_2BeF_4}
  • C (NH4)BeF3\mathrm{(NH_4)BeF_3}
  • D H3NBeF3\mathrm{H_3NBeF_3}

Step-by-Step Verified Solution

BeO+NH3+HF⟶(NH4)2BeF4(A)⟶ΔBeF2+NH4 F\mathrm{BeO}+\mathrm{NH}_{3}+\mathrm{HF} \longrightarrow\left(\mathrm{NH}_{4}\right)_{2} \underset{(\mathrm{A})}{\mathrm{BeF}_{4}} \stackrel{\Delta}{\longrightarrow} \mathrm{BeF}_{2}+\mathrm{NH}_{4} \mathrm{~F}

Compound A\mathrm{A} is (NH4)2BeF4\left(\mathrm{NH}_{4}\right)_{2} \mathrm{BeF}_{4}

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