Verified Solution • 2025–26 Session moderate

QJEEM23Che326: JEE Main 2023 Chemistry - Class 11 JEEM23Che326 Solution: When 0.01 mol of an organic compound containing 60% carbon was…

When 0.01 mol of an organic compound containing 60% carbon was burnt completely, 4.4 g of CO 2_2 was produced. The molar mass of compound is _____________ g mol −1^{-1} (Nearest integer).

Step-by-Step Verified Solution

Number of moles of CO2=4.444=0.1C{O_2} = {{4.4} \over {44}} = 0.1

∴\therefore Number of moles of C in 1 mole of compound = 10

∴\therefore 120=60100×(x)120 = {{60} \over {100}} \times (x) [where x is molar mass of OC]

Molar mass = 200 g mol −1^{-1}

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring