Verified Solution • 2025–26 Session moderate

QJEEM23Chdb5e: JEE Main 2023 Chemistry - Class 11 JEEM23Chdb5e Solution: In Carius tube, an organic compound ' ' is treated with sodium…

In Carius tube, an organic compound ' X\mathrm{X} ' is treated with sodium peroxide to form a mineral acid 'Y'.

The solution of BaCl2\mathrm{BaCl}_{2} is added to ' Y\mathrm{Y} ' to form a precipitate 'Z'. 'Z' is used for the quantitative estimation of an extra element. ' X\mathrm{X} ' could be

Multiple Choice Options

  • A Cytosine
  • B Methionine
  • C Chloroxylenol
  • D A nucleotide

Step-by-Step Verified Solution

X⟶Na2O2Y⟶BaCl2Z[BaSO4]\mathrm{X} \stackrel{\mathrm{Na}_2 \mathrm{O}_2}{\longrightarrow} \mathrm{Y} \stackrel{\mathrm{BaCl}_2}{\longrightarrow} \underset{\left[\mathrm{BaSO}_4\right]}{\mathrm{Z}}

Methionine: C5H11NO2S\mathrm{C}_5 \mathrm{H}_{11} \mathrm{NO}_2 \mathrm{S}

JEE Main 2023 (Online) 10th April Evening Shift Chemistry - Practical Organic Chemistry Question 24 English Explanation

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