Verified Solution • 2025–26 Session moderate

QJEEM23Chd729: JEE Main 2023 Chemistry - Class 12 JEEM23Chd729 Solution: K 2 Cr 2 O 7 paper acidified with dilute H 2 SO 4 turns green…

K2Cr2O7 paper acidified with dilute H2SO4 turns green when exposed to :

Multiple Choice Options

  • A Sulphur dioxide
  • B Sulphur trioxide
  • C Hydrogen sulphide
  • D Carbon dioxide

Step-by-Step Verified Solution

SO2\mathrm{SO}_{2} gets oxidised in presence of K2Cr2O7\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7} and it converts to Cr+3\mathrm{Cr}^{+3} in presence of dil. H2SO4\mathrm{H}_{2} \mathrm{SO}_{4} .

Similarly, H2 S\mathrm{H}_{2} \mathrm{~S} can also get oxidized to sulphur.

However, most appropriate is (A) Sulphur dioxide.

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