Verified Solution • 2025–26 Session moderate

QJEEM23Chd5c0: JEE Main 2023 Chemistry - Class 12 JEEM23Chd5c0 Solution: A cubic solid is made up of two elements X and Y. Atoms of X…

A cubic solid is made up of two elements X and Y. Atoms of X are present on every alternate corner and one at the center of cube. Y is at 13rd\frac{1}{3}^{\mathrm{rd}} of the total faces. The empirical formula of the compound is :

Multiple Choice Options

  • A X2Y1.5\mathrm{{X_2}{Y_{1.5}}}
  • B X3Y2\mathrm{{X_{3}}{Y_2}}
  • C XY2.5\mathrm{X{Y_{2.5}}}
  • D X2.5Y\mathrm{{X_{2.5}}Y}

Step-by-Step Verified Solution

amp; Number of X particles =4×18+1=1.5amp; Number of Y particles =6×13×12=1amp;∴ Empirical formula =X1.5Y1=X3Y2\begin{aligned} & \text { Number of } X \text { particles }=4 \times \frac{1}{8}+1=1.5 \\\\ & \text { Number of } Y \text { particles }=6 \times \frac{1}{3} \times \frac{1}{2}=1 \\\\ & \therefore \text { Empirical formula }=X_{1.5} Y_1=X_3 Y_2\end{aligned}

Related Learning Resources & Exam Preparation