Verified Solution • 2025–26 Session moderate

QJEEM23Chd2e8: JEE Main 2023 Chemistry - Class 11 JEEM23Chd2e8 Solution: Given below are two reactions, involved in the commercial…

Given below are two reactions, involved in the commercial production of dihydrogen (H 2_2 ). The two reactions are carried out at temperature "T 1_1 " and "T 2_2 ", respectively

C(s)+H2O(g)⟶T1CO(g)+H2(g)

CO(g)+H2O(g)⟶CatalystT2CO2(g)+H2(g)CO(g) + {H_2}O(g)\mathrel{\mathop{\kern0pt\longrightarrow}\limits_{Catalyst}^{{T_2}}} C{O_2}(g) + {H_2}(g)

The temperatures T 1_1 and T 2_2 are correctly related as :

Multiple Choice Options

  • A T 1_1 < T 2_2
  • B T 1_1 = T 2_2
  • C T 1_1 = 100 K, T 2_2 = 1270 K
  • D T 1_1 > T 2_2

Step-by-Step Verified Solution

These reactions are part of the water-gas shift reaction used in the industrial production of hydrogen. The first reaction is the endothermic steam reforming of coal (carbon), while the second reaction is the exothermic water-gas shift reaction.

  1. Carbon reacts with steam at high temperatures (around 1000°C or 1273 K) to form carbon monoxide and hydrogen:

    C(s) + H 2_2 O(g) →T1\xrightarrow[T_1]{} CO(g) + H 2_2 (g)


  2. Then carbon monoxide reacts with steam in the presence of a catalyst to produce carbon dioxide and more hydrogen:

    CO(g) + H 2_2 O(g) →Catalyst[T2]\xrightarrow[Catalyst]{[T_2]} CO 2_2 (g) + H 2_2 (g)

Since the first reaction is endothermic (absorbs heat), it requires a higher temperature to proceed than the second reaction, which is exothermic (releases heat). Therefore, the temperature T 1_1 should be higher than T 2_2 .

Related Learning Resources & Exam Preparation