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QJEEM23Chd1e4: JEE Main 2023 Chemistry - Class 12 JEEM23Chd1e4 Solution: Match List I with List II .tg…

Match List I with List II

List I List II
A. JEE Main 2023 (Online) 30th January Morning Shift Chemistry - Haloalkanes and Haloarenes Question 52 English 1 I. Fittig reaction
B. JEE Main 2023 (Online) 30th January Morning Shift Chemistry - Haloalkanes and Haloarenes Question 52 English 2 II. Wurtz Fittig reaction
C. JEE Main 2023 (Online) 30th January Morning Shift Chemistry - Haloalkanes and Haloarenes Question 52 English 3 III. Finkelstein reaction
D. C5H5C1+NaI→C2H5I+NaCl\mathrm{C_5H_5C1+NaI\to C_2H_5I+NaCl} IV. Sandemyer reaction

Choose the correct answer from the options given below :

Multiple Choice Options

  • A A - IV, B - II, C - III, D - I
  • B A - II, B - I, C - IV, D - III
  • C A - II, B - I, C - III, D - IV
  • D A - III, B - II, C - IV, D - I

Step-by-Step Verified Solution

JEE Main 2023 (Online) 30th January Morning Shift Chemistry - Haloalkanes and Haloarenes Question 52 English Explanation 1

JEE Main 2023 (Online) 30th January Morning Shift Chemistry - Haloalkanes and Haloarenes Question 52 English Explanation 2

JEE Main 2023 (Online) 30th January Morning Shift Chemistry - Haloalkanes and Haloarenes Question 52 English Explanation 3

(D) C2H5Cl+Nal⟶C2H5l+NaCl\mathrm{C_2H_5Cl+Nal\longrightarrow C_2H_5l+NaCl} (Finkelstein reaction)

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