Verified Solution • 2025–26 Session moderate

QJEEM23Chbb82: JEE Main 2023 Chemistry - Class 12 JEEM23Chbb82 Solution: The number of correct statement/s from the following is…

The number of correct statement/s from the following is __________

A. Larger the activation energy, smaller is the value of the rate constant.

B. The higher is the activation energy, higher is the value of the temperature coefficient.

C. At lower temperatures, increase in temperature causes more change in the value of k than at higher temperature

D. A plot of ln⁡k vs 1T is a straight line with slope equal to −EaR

Step-by-Step Verified Solution

(A) k=Ae−EaRT(Ea↑k↓)k=A e^{-\frac{E_{a}}{R T}}\left(E_{a} \uparrow k \downarrow\right)

(B) ln⁡k=ln⁡A−EaRT\ln k=\ln A-\frac{E_{a}}{R T}

1k⋅dkdT=+EaRT2

Ea↑\mathrm{E}_{\mathrm{a}} \uparrow temp. coefficient ↑\uparrow

(C)
JEE Main 2023 (Online) 24th January Morning Shift Chemistry - Chemical Kinetics and Nuclear Chemistry Question 45 English Explanation

Option (C ) is wrong. Δ\Delta k may be greater or lesser depending on temperature.

(D) ln⁡k=ln⁡A−EaRT\ln k=\ln A-\frac{E_{a}}{R T}

Slope of ln⁡k\ln k vs 1T\frac{1}{T} is (−EaR)\left(\frac{-E_{a}}{R}\right)

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