Verified Solution • 2025–26 Session moderate

QJEEM23Chb9bf: JEE Main 2023 Chemistry - Class 12 JEEM23Chb9bf Solution: When ion is treated with , a white precipitate, appears in…

When Cu2+\mathrm{Cu}^{2+} ion is treated with KI\mathrm{KI} , a white precipitate, X\mathrm{X} appears in solution. The solution is titrated with sodium thiosulphate, the compound Y\mathrm{Y} is formed. X\mathrm{X} and Y\mathrm{Y} respectively are :

Multiple Choice Options

  • A .tg {border-collapse:collapse;border-spacing:0;} .tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px; overflow:hidden;padding:10px 5px;word-break:normal;} .tg th{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px; font-weight:normal;overflow:hidden;padding:10px 5px;word-break:normal;} .tg .tg-0lax{text-align:left;vertical-align:top} X=CuI2\mathrm{X=CuI_2} Y=Na2S4O6\mathrm{Y=Na_2S_4O_6}
  • B .tg {border-collapse:collapse;border-spacing:0;} .tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px; overflow:hidden;padding:10px 5px;word-break:normal;} .tg th{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px; font-weight:normal;overflow:hidden;padding:10px 5px;word-break:normal;} .tg .tg-0lax{text-align:left;vertical-align:top} X=Cu2I2\mathrm{X=Cu_2I_2} Y=Na2S4O6\mathrm{Y=Na_2S_4O_6}
  • C .tg {border-collapse:collapse;border-spacing:0;} .tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px; overflow:hidden;padding:10px 5px;word-break:normal;} .tg th{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px; font-weight:normal;overflow:hidden;padding:10px 5px;word-break:normal;} .tg .tg-0lax{text-align:left;vertical-align:top} X=CuI2\mathrm{X=CuI_2} Y=Na2S2O3\mathrm{Y=Na_2S_2O_3}
  • D .tg {border-collapse:collapse;border-spacing:0;} .tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px; overflow:hidden;padding:10px 5px;word-break:normal;} .tg th{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px; font-weight:normal;overflow:hidden;padding:10px 5px;word-break:normal;} .tg .tg-0lax{text-align:left;vertical-align:top} X=Cu2I2\mathrm{X=Cu_2I_2} Y=Na2S4O5\mathrm{Y=Na_2S_4O_5}

Step-by-Step Verified Solution

2Cu2++4KI⟶Cu2I2 White ppt. +I22 \mathrm{Cu}^{2+}+4 \mathrm{KI} \longrightarrow \underset{\text { White ppt. }}{\mathrm{Cu}_{2} \mathrm{I}_{2}}+\mathrm{I}_{2}

I2+Na2 S2O3⟶2Nal+Na2 S4O6\mathrm{I}_{2}+\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3} \longrightarrow 2 \mathrm{Nal}+\mathrm{Na}_{2} \mathrm{~S}_{4} \mathrm{O}_{6}

X=Cu2I2\mathrm{X}=\mathrm{Cu}_{2} \mathrm{I}_{2}

Y=Na2 S4O6\mathrm{Y}=\mathrm{Na}_{2} \mathrm{~S}_{4} \mathrm{O}_{6}

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring