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QJEEM23Chabe9: JEE Main 2023 Chemistry - Class 12 JEEM23Chabe9 Solution: Cobalt chloride when dissolved in water forms pink colored…

Cobalt chloride when dissolved in water forms pink colored complex X‾\underline{\mathrm{X}} which has octahedral geometry. This solution on treating with conc HCl\mathrm{HCl} forms deep blue complex, Y‾\underline{\mathrm{Y}} which has a Z‾\underline{\mathrm{Z}} geometry. X,Y\mathrm{X}, \mathrm{Y} and Z\mathrm{Z} , respectively, are

Multiple Choice Options

  • A X=[Co(H2O)6]2+,Y=[CoCl4]2−,Z=\mathrm{X}=\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}, \mathrm{Y}=\left[\mathrm{CoCl}_{4}\right]^{2-}, \mathrm{Z}= Tetrahedral
  • B X=[Co(H2O)6]2+,Y=[CoCl6]3−,Z=\mathrm{X}=\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}, \mathrm{Y}=\left[\mathrm{CoCl}_{6}\right]^{3-}, \mathrm{Z}= Octahedral
  • C X=[Co(H2O)4Cl2]+,Y=[CoCl4]2−,Z=\mathrm{X}=\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4} \mathrm{Cl}_{2}\right]^{+}, \mathrm{Y}=\left[\mathrm{CoCl}_{4}\right]^{2-}, \mathrm{Z}= Tetrahedral
  • D X=[Co(H2O)6]3+,Y=[CoCl6]3−,Z=\mathrm{X}=\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}, \mathrm{Y}=\left[\mathrm{CoCl}_{6}\right]^{3-}, \mathrm{Z}= Octahedral

Step-by-Step Verified Solution

JEE Main 2023 (Online) 31st January Morning Shift Chemistry - Coordination Compounds Question 107 English Explanation

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