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QJEEM23Cha9c7: JEE Main 2023 Chemistry - Class 12 JEEM23Cha9c7 Solution: In the following reactions, the total number of oxygen atoms in …

In the following reactions, the total number of oxygen atoms in X and Y is ___________.

Na 2_2 O + H 2_2 O →\to 2X

Cl 2_2 O 7_7 + H 2_2 O →\to 2Y

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amp;Na2O+H2O⟶2NaOH(X)amp;Cl2O7+H2O⟶2HClO4(Y)\begin{aligned}& \mathrm{Na}_2 \mathrm{O}+\mathrm{H}_2 \mathrm{O} \longrightarrow 2 \mathrm{NaOH}(\mathrm{X}) \\\\& \mathrm{Cl}_2 \mathrm{O}_7+\mathrm{H}_2 \mathrm{O} \longrightarrow 2 \mathrm{HClO}_4(\mathrm{Y})\end{aligned}

XX has one OO and YY has four OO

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